Field Notes / Σ /sym/b9b97b
id=680697 · host=uk.mattivster.me · 2026-08-30 18:44Z
∑_{k=1}^{n} k = n(n+1)/2
5φ² + 4φ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
428K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
350K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
141K
5y² + 2y + 3 = 0
11α² + 9α + 3 = 0
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O